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() , , 1/12 .

, . , , , . . ( ):

Mr(CnDm)=Ar(C) n + Ar(D) m

:

Mr(NH3) = r(N) 1 + Ar() 3 = 14 1 + 1 3 = 17

r(3O4) = Ar() 3 + Ar() 1 + Ar() 4 = 1 3 + 31 1 + 16 4 = 98

(. . .), ( m):

m(NH3) = ma(N) 1 + ma() 3 = 14 . . . 1 + 1 . . . 3 = 17 . . .

m(3O4) = m() 3 + m() 1 + ma() 4 = 1 . . . 3 + 31 . . . 1 + 16 . . . 4 = 98 . . .

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.

( ) , .

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, CnDm

1

, Fe2O3.

, , Fe2O3, 1 :

m(Fe) = m(Fe2O3) (Fe) = 1 0,70 = 0,70 = 700

1, 100%. .

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